Stargate: Wraith cruiser self destruct yield
Posted: Sat Jan 26, 2008 3:24 pm
Ok, this is going to take quite some time, and below there's quite a lot of stuff to read and data to pick from, some may be redundant, or important, maybe we will be missing the important details, but I'm sure that at least, it's a good start and provides enough matter to adress the question.
I've been having this discussion started, stopped and resumed over the coure of a year later with someone else, had several things said here and there, so I'm trying to assemble the bits now.
While, at first, it seemed to be a totally unexploitable situation, some search and talk revealed that there was more to learn there, and possibly figures to derive about a Wraith cruiser' critical mass. This would be a low end, anyway, since we don't really know how the self destruct works, what reactant is used, how the reaction occurs exactly, nor if it was planned to be a maximum yield. Besides, the ship itself is far from being in its prime.
That said, I think we have another case at hand where we can estimate the power a Wraith cruiser can generate for a self destruct.
In Submersion, a Wraith cruiser was shot down by Atlantis' defenses when the Wraith sent a first wave against the planet. The ship crashed in the ocean, and sunk down there, settled on the seabed and remained there for a long time.
Surprisingly, the queen was inside. Maybe she was a minor queen, well, we don't know (that would be preferable for a number of reasons, but it's not the point).
Towards the end of the episode, the queen arms the ship's self destruct, and McKay, as usual, is panicked.
There's a good reason for that.
We've been thinking about what's necessary to cause enough damage.
Here's a copy of the talk:
I've been having this discussion started, stopped and resumed over the coure of a year later with someone else, had several things said here and there, so I'm trying to assemble the bits now.
While, at first, it seemed to be a totally unexploitable situation, some search and talk revealed that there was more to learn there, and possibly figures to derive about a Wraith cruiser' critical mass. This would be a low end, anyway, since we don't really know how the self destruct works, what reactant is used, how the reaction occurs exactly, nor if it was planned to be a maximum yield. Besides, the ship itself is far from being in its prime.
That said, I think we have another case at hand where we can estimate the power a Wraith cruiser can generate for a self destruct.
In Submersion, a Wraith cruiser was shot down by Atlantis' defenses when the Wraith sent a first wave against the planet. The ship crashed in the ocean, and sunk down there, settled on the seabed and remained there for a long time.
Surprisingly, the queen was inside. Maybe she was a minor queen, well, we don't know (that would be preferable for a number of reasons, but it's not the point).
Towards the end of the episode, the queen arms the ship's self destruct, and McKay, as usual, is panicked.
There's a good reason for that.
And more...TEYLA: Wait!
(She forces herself to continue her probe of the Queen's mind, and sees a red light begin to pulse on the control panel of the cruiser.
Teyla raises her head, her eyes open.)
TEYLA: She has activated the self-destruct device of the Wraith cruiser. It is set to detonate within two hours.
(The Queen looks round at John and grins.)
SHEPPARD: So – *not* an empty threat.
We've been thinking about what's necessary to cause enough damage.
Here's a copy of the talk:
Me wrote:
I'm looking at three webpages for the moment:
Wong's Calculator, to see how much energy this system estimates will be necessary to break the crust.
This thread, which suggests that the fragmentation part of Wong's calculator may be well under what's correct.
The Golevka test was based on a detonation of a 10 MT nukes, and it didn't shatter the asteroid down to 10 meters wide fragments.
The calculator says that only 148.9 kilotons are necessary for a 530 meters wide rocky asteroid. Wong's number is 67.16 times inferior to what the test returned, and the asteroid was not shattered at all.
Then, I suppose that as it always happens with energy figures when you account for volume and radii, the thicker the asteroid, the bigger the ratio would be.
Then, I look at Mount St Helens' eruption, which indicates a total energy release of 24 megatons thermal energy (7 by blast, rest through release of heat), for 401 m of matter removed (height comparison at the top of the table).
If anything, the Golevka test points to a range much closer to St Helens's figures than Wong's estimations.
Then, let's think about the crust thickness that that depth. Earth's crust has a minimal thickness of 5 km.
So let's say that the bomb is planted in an asteroid being 10 km wide.
Wong's calc says:
Fragmentation energy: 1 gigaton.
Ok, we're already in the gigaton range.
Now, using the former ratio, the figure would already be around 67.16 gigatons, and a final yield a thousand times bigger than that.
That's for using a ratio which could likely be inferior, possibly by one order of magnitude, to what the real ratio would be in the end.
It's funny to look at wikipedia's comparison between the Richter scale and the TNT equivalence.
The ratio could, and would probably need to be a hell lot bigger, if the resulting explosion would be expected to defeat water pressure, because I suppose much of the water actually help keeping a huge pressure on that layer of rock.
I've recently seen an interesting documentary, showing how the ice cap melting, increasing the volume of liquid water, would increase the pressure on zones of seismic activity, for examples in zones near Seattle and Tokyo, because of the presence of the Ring of Fire, increasing the rate and magnitude of earthquakes.
Meaning that where there's no such a rift (there's no sign of submarine mountain range, nor any volcano as far as I can remember in the episode), the pressure is logically going to homogeneously compress the rock layer and keep the lava underneath.
Which means that a good deal of energy will be needed to let the lava burst, and have the eruption multiply the initial blast by a thousand (which, of course, is a figure they totally made up).
Finally, you were quite right, in january, when you considered that something could be obtained from this episode, and we could really be looking at something really big.
Now, I may have done a few things wrong, but I can't tell for the moment, so if you feel like giving it a look.
That's for the first part. There was lots of stuff to explore, so I spent some time lurking around and trying to snif some detailed page about massive geological events.Other person wrote:
Some interesting thoughts here to be sure. A lot of people use Wongs calculator assuming it infallible but I would say something like St. Helen's is a much more reliable benchmark for this type of event since it, you know, actually happened.
Your bringing up the water pressure also got me to thinking, and if I'm on the right track here get ready for the numbers to shoot WAY up.
They say that the cruiser blowing up will also pose a serious threat to, if not outright destroy Atlantis?
How?
Blowing a hole in the bottem of the ocean wouldn't do it, unless we're talking about a hole big enough to basically flash boil most of the water under the city in an allmighty explosion. Or by creating one with enough energy to send rocks and shit up through however many miles of ocean to physically blow the city apart.
So we're looking at a few more potential numbers here.
Warsie style High end
The crusier exploding will destroy atlantis by itself: This would require that the cruiser's reactor be able to vaporise god knows how many square miles of seawater to be able to create a convincing, and fast, enough blast wave to actually destroy or badly damage the city resting on the surface.
More reasonable interpretation
The cruiser will cause enough damage to the planet to make it do this: I'm not sure if this is even physically possible or not, though I'm leaning toward not. The dialog says it is though so we'll roll with it I guess, in the interest of a lower estimate. Basically the cruiser will have to open up such a massive fissure in the ocean floor that the energy released from it will do basically what I wrote about above. Also the actual reactor explosion shouldn't be less than roughly 1/1000 of the energy required to do this.
Another thing to consider here as well is the city shields. I can't remember if they have them available at this point but if they do they increase the numbers further.
To destroy the city with its shields up you're going to either have to create such a powerful blast that the city is destroyed almost instantly, before they can be raised to protect it. This will mean that a slow moving "depth charge" type wave wouldn't be viable as they could raise the shields when detecting the initial explosion long before the wave made it to the surface. It would basically mean that flash vaporization of mass quanties of ocean would be required, either to destroy most of the interveening water and shorten the distance the shockwave would have to travel, or to just blow the city up with raw energy despite the interveening water.
Now I don't know much about how undersea explosions actually work so I might be completely off and wrong about things like the shockwaves but I think we've hit on something important here.
When estimating how much energy this is going to take we must keep in mind that the blast, either from the cruiser or planet, is going to have to also be capable of reaching and damaging or destroying atlantis, likely before it can raise its shields.
Here's the dialog from the episode that's relevant.
So they think it's going to happen fast enough that Atlantis will "never see it coming" and also that it's going to be well within the blast radius, which probably means destruction is likely rather than just damage.So it won’t just be us that’s affected.
ZELENKA: No. Atlantis will be affected as well. It’s well within the blast radius.
WEIR: And we have no way to warn them?
McKAY: They’d never even see it coming.
If we can take a reasonable low end estimate for the depth of the ocean and then calculate a hemispherical region of water to boil/vape this can probably be calced.